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Melting Ice with a Carnot Engine?
A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water. In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 4.25×10^−2 kg.
Throughout this problem use Lsub f=3.34 * 10^5 J/kg for the heat of fusion for water.
A) During this time, how much work W is performed by the engine?
1 Answer
- Dr DLv 71 decade agoFavourite answer
Well, energy imparted to the ice
= 4.25×10^−2 * 3.34 * 10^5
= 14195 J
= 14.195 kJ
This is the heat given off by the engine.
For a carnot cycle, η = (Th - Tc) / Th
= 100 / 373
= W / Qin = W / (W + Qout)
373W = 100W + 100Qout
W = 100*Qout / 273
= 100 * 14.195 / 273
= 5.2 kJ
