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UnderOath1617
Lv 4
onto functions?
If f: X --> Y and g: Y --> Z are functions and g º f is onto, must both f and g be onto? Prove or give a counterexample.
Any help is appreciated!
1 Answer
Relevance
- iluxaLv 51 decade agoFavourite answer
Counter-example:
Let X be all integers
Let Y be all integers in [0..99] interval
Let Z be all integers in [0..2] interval
let f be "x mod 10"
let g be "y mod 3"
f is not onto, yet g º f is onto
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