If the area of a square is 11 +√112, calculate its perimeter.?

if you are given the area (11 + √112) units^2, then the side is:

s^2 = area

s = √(11 + 4√7)

perimeter = 4s = 4√(11 + 4√7) units

the radical of the radical can be simplified to:

√(11 + 4√7) = 2 + √7

so...the perimeter is: 8 + 4√7 units

MAD

If the area of a square is 11 +√112,

calculate its perimeter.

If area = s^2, perimeter = 4s

s^2 = 11 + 4√7

s = 4.6458

4s = 18.5832

The perimeter of the square is 18.5832.

A = 11+√112 = s²

so s = √(11+√112)

perimeter = 4s

perimeter = 4√(11+√112)

this can be simplified a bit

√112 = √(7•4•4) = 4√7

perimeter = 4√(11+4√7)