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could someone please explain to me?
In a hypothetical population of 1,000 people, tests of blood-type genes show that 160 have the genotype AA, 480 have the genotype AB, and 360 have the genotype BB. What is the frequency of the B allele?
A) 0.001
B) 0.002
C) 0.100
D) 0.400
E) 0.600
the answer is E. Can someone please teach me how to do it?
could someone please check this for me?
p^2 + 2pq + q^2 = 1
0.16 + 0.48 + 0.36 = 1 (from the question)
hence, q^2 = 0.36
then, q= square root of 0.36
= 0.6
so, it's that what we're looking for? q=0.6? is that equals to the frequency of B allele? i am not so sure on this one..
2 Answers
- SmegheadLv 71 decade agoFavourite answer
Yep, you're absolutely correct. Here's another way to look at it. There are 1000 people, each with two alleles, so there are 2000 total alleles. There are 480 people with one B allele (the AB people), and 360 people with two B alleles (BB people). So there are 480 + 2*360 = 1200 total B alleles out of 2000 total alleles. 1200/2000 = 0.600.
- 1 decade ago
Use the Hardy Weinberg equations:
1. Find q^2 (q-squared) (percent of homozygous recessive in the population). This percent is
usually given or one determines the percent of recessives in a population.
2. From q^2, find q (by using a calculator, take the square root of q^2).
3. From q, find p by using the haploid formula p = 1-q.
4. Find p^2 by multiplying p by itself (p p).
5. Use formula 2 (p x q) to determine percent heterozygous in the population.
6. To double-check your math, use diploid formula from above. All three
percentages should be:
p^2+ 2pq + q^2= 1, or 100%
