Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

bummer
Lv 6
bummer asked in Science & MathematicsMathematics · 1 decade ago

MacLaurin series> i don't understand this, so please help me?

obtain the first 4 terms in the MacLaurin series for e^-X2

i really have no idea. what should i do first? please help me, i haven't learned this yet and i need to know.

1 Answer

Relevance
  • Anonymous
    1 decade ago
    Favourite answer

    Effectively you keep differentiating to get the next function and sub in 0...:

    f(x) = e^(-2x):

    when x=0, f(x) = 1

    f'(x) = -2e^(-2x) [first derivative]

    when x=0, f'(x) = -2

    f''(x) = 4e^(-2x) [second derivative]

    when x=0, f''(x) = 4

    f''(x) = -8e^(-2x) [third derivative]

    when x=0, f''(x) = -8

    f''(x) = 16e^(-2x) [fourth derivative]

    when x=0, f''(x) = 16

    so.. e^(-2x) = 1 + -2x/1! + 4x^2/2! + -8x^3/3! + 16x^4/4!

    The numbers before the x's are the stuff we worked out above followed by x of an increasing power and divided by an increasing factorial

    so e^(-2x) = 1 - 2x + 2x^2 - 4/3 x^3 + 2/3 x^4

Still have questions? Get answers by asking now.